Summary: Awk script help

[Hickey, Michael]

The overwhelming majority submitted the following:

awk '$3>=15{print $3}'

Thanks to all those who responded.

Regards,
Mike



>  -----Original Message-----
> From: 	Hickey, Michael  
> Sent:	Tuesday, April 22, 2003 11:05 AM
> To:	Sun Managers Mailing List (E-mail)
> Subject:	Awk script help
> 
> Can someone push me in the right direction of the proper syntax to take a
> file,
> dr.out containing multiple rows and 3 fields as below, and print only the
> lines that 
> have a number >= 15 in field 3?
> 
> 04/12/03 20:56 15.3
> 04/12/03 21:56 15.3
> 04/12/03 22:56 15.3
> 04/12/03 23:57 18.5
> 
> Thanks in advance.
> 
> Mike
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